\(\int \frac {\log ^3(c x)}{x} \, dx\) [19]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [A] (verification not implemented)
   Sympy [A] (verification not implemented)
   Maxima [A] (verification not implemented)
   Giac [A] (verification not implemented)
   Mupad [B] (verification not implemented)

Optimal result

Integrand size = 10, antiderivative size = 10 \[ \int \frac {\log ^3(c x)}{x} \, dx=\frac {1}{4} \log ^4(c x) \]

[Out]

1/4*ln(c*x)^4

Rubi [A] (verified)

Time = 0.01 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {2339, 30} \[ \int \frac {\log ^3(c x)}{x} \, dx=\frac {1}{4} \log ^4(c x) \]

[In]

Int[Log[c*x]^3/x,x]

[Out]

Log[c*x]^4/4

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rule 2339

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)/(x_), x_Symbol] :> Dist[1/(b*n), Subst[Int[x^p, x], x, a + b*L
og[c*x^n]], x] /; FreeQ[{a, b, c, n, p}, x]

Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int x^3 \, dx,x,\log (c x)\right ) \\ & = \frac {1}{4} \log ^4(c x) \\ \end{align*}

Mathematica [A] (verified)

Time = 0.00 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00 \[ \int \frac {\log ^3(c x)}{x} \, dx=\frac {1}{4} \log ^4(c x) \]

[In]

Integrate[Log[c*x]^3/x,x]

[Out]

Log[c*x]^4/4

Maple [A] (verified)

Time = 0.22 (sec) , antiderivative size = 9, normalized size of antiderivative = 0.90

method result size
derivativedivides \(\frac {\ln \left (x c \right )^{4}}{4}\) \(9\)
default \(\frac {\ln \left (x c \right )^{4}}{4}\) \(9\)
norman \(\frac {\ln \left (x c \right )^{4}}{4}\) \(9\)
risch \(\frac {\ln \left (x c \right )^{4}}{4}\) \(9\)
parts \(\ln \left (x c \right )^{3} \ln \left (x \right )-\frac {3 \ln \left (x c \right )^{2} \ln \left (x \right )^{2}}{2}+\ln \left (x c \right ) \ln \left (x \right )^{3}-\frac {\ln \left (x \right )^{4}}{4}\) \(38\)

[In]

int(ln(x*c)^3/x,x,method=_RETURNVERBOSE)

[Out]

1/4*ln(x*c)^4

Fricas [A] (verification not implemented)

none

Time = 0.30 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.80 \[ \int \frac {\log ^3(c x)}{x} \, dx=\frac {1}{4} \, \log \left (c x\right )^{4} \]

[In]

integrate(log(c*x)^3/x,x, algorithm="fricas")

[Out]

1/4*log(c*x)^4

Sympy [A] (verification not implemented)

Time = 0.04 (sec) , antiderivative size = 7, normalized size of antiderivative = 0.70 \[ \int \frac {\log ^3(c x)}{x} \, dx=\frac {\log {\left (c x \right )}^{4}}{4} \]

[In]

integrate(ln(c*x)**3/x,x)

[Out]

log(c*x)**4/4

Maxima [A] (verification not implemented)

none

Time = 0.22 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.80 \[ \int \frac {\log ^3(c x)}{x} \, dx=\frac {1}{4} \, \log \left (c x\right )^{4} \]

[In]

integrate(log(c*x)^3/x,x, algorithm="maxima")

[Out]

1/4*log(c*x)^4

Giac [A] (verification not implemented)

none

Time = 0.31 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.80 \[ \int \frac {\log ^3(c x)}{x} \, dx=\frac {1}{4} \, \log \left (c x\right )^{4} \]

[In]

integrate(log(c*x)^3/x,x, algorithm="giac")

[Out]

1/4*log(c*x)^4

Mupad [B] (verification not implemented)

Time = 0.24 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.80 \[ \int \frac {\log ^3(c x)}{x} \, dx=\frac {{\ln \left (c\,x\right )}^4}{4} \]

[In]

int(log(c*x)^3/x,x)

[Out]

log(c*x)^4/4